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標題:
F4 Maths (Log) Quickly please!
發問:
(log x^4 + log y^2) / log x y^ (1/2) =? Ans: 4 What are the steps?
(log x^4 + log y^2) / log x y^ (1/2) = (4log x + 2log y) / (log x + log y^(1/2)) = (4log x + 2log y) / (log x + (1/2)log y) = 2(2log x + logy) / (1/2) (2log x + log y) = 2 / (1/2) = 4
其他解答:
(log x^4 + log y^2) / log x y^ (1/2) =(4logx+2logy)/(logx+1/2logy) =2(2logx+logy)/(logx+1/2logy) =2(2logx+logy)/1/2(2logx+logy) =2/(1/2) =4
F4 Maths (Log) Quickly please!
發問:
(log x^4 + log y^2) / log x y^ (1/2) =? Ans: 4 What are the steps?
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最佳解答:(log x^4 + log y^2) / log x y^ (1/2) = (4log x + 2log y) / (log x + log y^(1/2)) = (4log x + 2log y) / (log x + (1/2)log y) = 2(2log x + logy) / (1/2) (2log x + log y) = 2 / (1/2) = 4
其他解答:
(log x^4 + log y^2) / log x y^ (1/2) =(4logx+2logy)/(logx+1/2logy) =2(2logx+logy)/(logx+1/2logy) =2(2logx+logy)/1/2(2logx+logy) =2/(1/2) =4
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