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algerba 2
發問:
. The drag force on a boat varies jointly as the wetted surface area and the square of the velocity of a boat. If a boat going 6.5 mph experiences a drag force of 86 N when the wetted surface area is 41.2 ft2 , how fast must a boat with 28.5 ft2 of wetted surface area go in order to experience a drag force of... 顯示更多 . The drag force on a boat varies jointly as the wetted surface area and the square of the velocity of a boat. If a boat going 6.5 mph experiences a drag force of 86 N when the wetted surface area is 41.2 ft2 , how fast must a boat with 28.5 ft2 of wetted surface area go in order to experience a drag force of 94N? can i have the steps?
Let F be the drag force in N. F = kAv^2 where A is the wetted surface in square-feet v is the velocity in mph and k is a constant 86 = k(41.2).(6.5)^2 and 94 = k(28.5).v^2 Dividing, 94/86 = (28.5)v^2/(41.2 x 6.5^2) v = 8.17 mph
其他解答:
algerba 2
發問:
. The drag force on a boat varies jointly as the wetted surface area and the square of the velocity of a boat. If a boat going 6.5 mph experiences a drag force of 86 N when the wetted surface area is 41.2 ft2 , how fast must a boat with 28.5 ft2 of wetted surface area go in order to experience a drag force of... 顯示更多 . The drag force on a boat varies jointly as the wetted surface area and the square of the velocity of a boat. If a boat going 6.5 mph experiences a drag force of 86 N when the wetted surface area is 41.2 ft2 , how fast must a boat with 28.5 ft2 of wetted surface area go in order to experience a drag force of 94N? can i have the steps?
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最佳解答:Let F be the drag force in N. F = kAv^2 where A is the wetted surface in square-feet v is the velocity in mph and k is a constant 86 = k(41.2).(6.5)^2 and 94 = k(28.5).v^2 Dividing, 94/86 = (28.5)v^2/(41.2 x 6.5^2) v = 8.17 mph
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