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標題:

ce chem 2003 q33

發問:

Ethane reacts with bromine under suitable condition. Which of the following statements concerning this reaction is/are correct? (1) The reaction occurs readily in the dark. (2) The reaction is substitution. (3) The reaction gives a mixture of organic products. Why (3) is correct? HBr is organic? 更新: The statement means that the mixture of products CH3Br(g), CH2Br2(g), CHBr3(g) and CBr4(g) are organic products but not for HBr(g)<< 更新 2: HBr is not a product?

最佳解答:

(1) False As the UV light and high temperature needed for the reaction, only alkene can react with halogens in the dark. (2) True It is a free radical substitution (3) True CH4(g) + Br2(g) -> CH3Br(g) + HBr(g) CH3Cl(g) + Br2(g) -> CH2Br2(g) + HBr(g) CH2Cl2(g) + Br2(g) -> CHBr3(g) + HBr(g) CHBr3(g) + Br2(g) -> CBr4(g) + HBr(g) The statement means that the mixture of products CH3Br(g), CH2Br2(g), CHBr3(g) and CBr4(g) are organic products but not for HBr(g) HBr(g) is not an organic product. 2010-04-11 18:43:58 補充: Of course, HBr is a product However, the question was asked you the reaction whether gives the MIXTURE of organic products. The mixture of CH3Br(g), CH2Br2(g), CHBr3(g) and CBr4(g) is the MIXTURE of organic products. 個問題係有無? 而唔係HBr 係唔係organic product

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其他解答:

HBr is not a organic compound, but Ethane reacts with bromine water will form Tetrabromomethane CBr4 through sunlight, it is organic compound.
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